Students and Teachers Forum
Let, E = set of people who speak English F = set of people who speak French Then, Total number of people, n(U) = 100 Number of people who speak English, n(E) = 72 Number of people who speak French, n(F) = 43 Number of people who speak .....
Let S, H and M represent the sets of students passed in Science, Health and Maths respectively. Then, Percentage of students who passed in mathematics, n(M) = 40% Percentage of students who passed in science, n(S) = .....
Let, Total number of students, n(U) = 95 Let x be any constant. Then, No. of student who like Mathematics, n(M) = 4x No. of students who like Science, n(S) = 5x No. of students who like both subjects, n(M∩S) = 10 No. of students who .....
Given, n (A) = 40 n (B) = 60 n (AUB) = 80 n (A ∩ B) = ? n0 (A) = ? n0 (B) = ? We know, n (AUB) = n(A) + n(B) – n(A∩B) Or, 80 = 40 + 60 – n(A∩B) Or, 80 = 100 – n(A∩B) Or, n(A∩B) = 100 – .....
Given, Total number of people, n(U) = 70 Number of people who like tea, n(T) = 37 Number of people who like milk, n(M) = 52 Number of people who like both tea and milk, n(T∩M) = ? Number of people who like tea only, no(T) = ? Venn .....
Let x be any constant. Then, Number of people who like modern songs, n(M) = 8x Number of people who like folk songs, n(F) = 9x Number of people who like both songs, .....
Given, n(A) = 12 and n(B) = 20, Minimum value of n(A ∪ B) = ? We know, n(A ∪ B) = n(A) + n(B) - n(A ∩ B) We get the minumum value of n(A ∪ B) when n(A ∩ B) is maximum. And for set A and B, n(A ∩ B) is .....
Let S and E be the set of students who passed in Science and English respectively. Then, Total percentage of students, n (U) = 100% Percentage of students who passed in Science only, no(S) = 45% Percentage of students who passed .....
Let F, B and C be the set of students who liked football, basketball and cricket respectively. Then, Total number of students, n (U) = 70 Number of students who like cricket, n (C) = 40 Number of students who like football, n(F) = .....
Let M and T be the set of people who liked milk and tea respectively. Then, Total number of people, n (U) = 150 Numbe of people who like milk only, n0 (M) = 30 Number of people who like tea only, n0 (T) = 20 Number of people .....
Let M and S denote the sets of students who like Mathematics and Science respectively. From question, Total number of students, n(U) = 95 Ration of number of students who like mathematics and science, n(M): n(S) = .....
Let, A and B denote the set of students who used the autorickshaw and bus respectively. From the question, Total number of students, n(U) = 131 Number of students who used autorickshaw, n(A) = 56 Number of students who used bus, n(B) = 103 Number .....
Let K, G and H represent the sets of people who read Kantipur, Gorkhapatra and Himalayan times respectively. Total number of students, n(U) = 100 Number of people who read Kantipur, n(K) = 65 Number of people who read Gorkhapatra, n(G) = 45 Number .....
Let, T and C denote the sets of people who like tea and coffee respectively. From the question, Percentage of people who like tea only, no(T) = 39% Percentage of people who like coffee only, no(C) = .....
Let, Total number of students, n(U) = 119 No. of students who like neither swimming nor driving, n (SUD)ˈ = 16 No. of students who like driving, n(D) = 69 No. of .....
Let, Percentage of people who like to travel Europe, n(E) = 50% Percentage of people who like to travel America, n(A) = 60% Percentage of people who like to travel Japan, n(J) = 40% Percentage of people who like to travel Europe and America, .....
Let, Total number of students, n(U) = 200 Number of students who play cricket, n(C) = 70 Number of students who play football, n(F) = 80 Number of students who play basketball, n(B) = 100 Number of students who play cricket and football only, .....
Given, n(A) = 10 n(B) = 25 For maximum number of element in set AUB, the set must be disjoint sets. Then, n(A∪B) = n(A) + n(B) .....
Given: n (U) = 90 n (P) = 50 n (Q) = 35 n (P ∪Q)ˈ = 15 .....
Let M and S be the set of students who like mathematics and science respectively. Then, Total number of students, n(U) = 95 Ratio of students who like mathematics and science, n(M): n(S) = 4:5 So, if x is any constant, n(M) = 4x .....
Given, n (T) = 80 n (M) = 70 n (T ∪ M) = 120 Number of people who like tea but not milk, n0 (T) = ? We have, n (T ∪ M) = n (T) + n (M) – n (T ∩ M) Or, 120 = 80 + 70 – n (T ∩ .....
Let A and B be the group of students who like grapes and mangoes respectively. Then, Total number of students, n (U) = 175 Number of students who like grapes, n (A) = 90 Number of students who like grapes only, n0 (A) = .....
Given, n0 (M) = 20 n (E) = 75 n (M ∩ E) = 50 Number of people who like mathematics, n (M) = ? We have, n0 (M) = n (M) – n (M ∩ E) Or, 20 = n (M) – 50 Or, n (M) = 50 + 20 .....
Solution: Given, Let A and B be the set of students who like Ice-cream and curd respectively. Now, Number of students who like ice-cream, n (A) = 60 Number of students who like curd, n (B) = 50 Number of students who .....
Given, n(A) = 80 n(B) = 65 For the least value of n (A∪B), the sets must be overlapping sets, with set B as the proper subset of A. Then, n(A∪B)= n(A) .....
Let A be the students who like Maths and B be the students who like Science. We have given, no(A) = 10, no(B) = 15 n(AUB) ' = 10 So, n(AUB) = n(U) - n(AUB)' = 50 .....
Given, U = {1, 2, 3, …….,10} A = {2, 4, 6, 8} B = {1, 2, 3, 4, 5} Now, A ∪ B = {2, 4, 6, 8} ∪ {1, 2, 3, 4, 5} = {1, 2, 3, 4, 5, 6, 8} And (A ∪B .....
Here, X, Y, Z are the subsets of U, n(X) = 48, n(Y) = 51, n(Z) = 40, n(X ∩ Y) = 11, n(Y ∩ Z) = 10, n(Z ∩ X) = 9 , n(X∩ Y ∩ Z) = 180 and n(U) = 120. n(X ∩ Y∩ Z) = ? We know, n(X∪ Y ∪Z) = n(X) + n(Y) + n(Z) .....
Let, M = Mathematics and E = English Given, Total no. of student, n(U) = 100 Number of students who like Mathematics, n(M) = 65 Number of students who like English, n(E) = 75 Nuber of students who like both .....
Let T and C be the set of people who like tea and coffee respectively. Then, Total number of people, n (U) = 350 Number of people who like tea, n (T) = 150 Number of people who like coffee, n (C) = 200 Number of people .....
Let F and C be the set of students who like football and cricket respectively. Then, Total number of students, n(U) = 200 Number of students who like football, n (F) = 150 Number of students who like cricket, n (C) = 120 According .....
Let A and B be the percentage of students playing basketball and cricket respectively. Given, Percentage of students who play basketball, n(A) = 45% Percentage of students who play cricket, n(B) .....
Here, n(A) = 40 n(B) = 60 n(A∪B) = 80 n(A∩B) = ? We know, n(A∪B) = n(A) + n(B) -n(A∩B) or, 80 = 40 + 60 – n(A∩B) or, n(A∩B) = 100 – 80 or, n(A∩B) = 20 Hence, n(A∩B) = .....
Let, No. of students who like football, n(F) = 18 No. of students who like volleyball, n(V) = 19 No. of students who like basketball, n(B) = 16 No. of students who like football only, no(F) = 6 No. of students who like volleyball only, no(V) = 9 No. .....
Let M and S be the set of students who passed in mathematics and science respectively. Then Total number of student, n (U) = 120 Number of students who passed in science only, no(S) = x (say) Then, number of students who passed in .....
Let, S and D denote the sets of people who like singing and dancing respectively. n(U) = 100 n(S) = 65 n(D) = 55 n(S∩D) = 35 n(S∪D)ˈ = ? The given information are shown in the Venn diagram. Now, from .....
Let, Total number of students, n(U) = 200 No. of students who succeeded in English, n(E) = 70 No. of students who succeeded in Mathematics, n(M) = 80 No. of students who succeeded in Nepali, n(N) = 60 No. of students who succeeded in English and .....
Given, A and B are two non-empty sets such that A ⊂ B and B ⊂ A. Here, A ⊂ B means that all elements of set A are also in set B. Similarly, B ⊂ A means that all elements of set B are also in set A. The conditions hold true .....
Given, A and B are two disjoint sets, We know, n (A ∪ B) = n(A) + n(B) - n(A ∩ B) For, disjoint sets, n(A ∩ B) is zero. So, the relation is given by, n (A ∪ B) = n(A) + n(B), which is the true relation for .....
Let A and B be any two sets. Then the union of two sets A and B is a set of elements which are both in sets A and B. It is written as A ∪ B. For example, Let A = {2, 4, 6, 8} and B = {1, 2, 3, 4, 5} then, A ∪ B = {1, 2, 3, 4, 5, 6, .....
Given, n(A) = 50 and n(B) = 80, Since, A ⊂ B, all the elements of set A is also the elements of set B. But n(A) is less than n(B). So, A is a proper subset of B. In that case, n(A) = n(A∩B) Then, n(A ∪ B) = n(B) .....
Let E and S be the set of students who like English and Science. Then, Total no.of students, n(U) = 50 Number of students who like only one subject, n0 (E) + n0 (S) = 35 Ratio of number of students who like both and who do not .....
Let M and E be the group of students who liked mathematics and English respectively. Then, Total percentage of students, n (U) = 100% Percentage of students who liked mathematics, n (M) = 60% Percentage of students who liked .....
Given, n(A ∩ B) = 10 n(A ∪ B) = 50 n(A)/n(B) = 2/3 ==> n(B) = 3/2 n(A) n(A) = ? We know, n(A ∪ B) = n(A) + n(B) – n(A ∩ B) Or, 50 = n(A) + 1.5 n(A) – 10 Or, .....
Given, n(A) = 12 n(B) = 20, Maximum value of n(A∪ B) = ? We know, n(A∪ B) = n(A) + n(B) - n(A ∩ B) We get the maximum value of n(AUB), when n(A ∩ B) is zero. So, the maximum value of n(A∪ B) = n(A) + n(B) .....
Let A = Set of people who like cold drinks. B = Set of people who like hot drinks. Then, Total number of people, n(A ∪ B) = 60 Number of people who like cold drinks, n(A) = 27 Number of people who like hot .....
Here, n(U) = 70 n(A) = 40 n(B) = 20 n(A∪B)ˈ = 15 n(A∩B) = ? We know, n(AUB) = n(U) - n(A∪B)ˈ Or, n(AUB) = 70 - 15 Or, .....
Let A be the number of students drinking tea and B be students drinking coffee. Let ‘x’ be students drinking both tea and coffee. From Venn diagram, Or, 80 -x + x + 26 – x + 17 = 120 Or, 123 – x = 120 Or,, x = 3 So, .....
Let, No. of people who like Dashain, n(D) = 45% No. of people who like Tihar, n(T) = 65% No. of people who like both festivals, n(D∩T) = 28% No. of people who like atleast one of the .....
Given, n(A - B) = 18 n(A ∪ B) = 70 and n(A ∩ B) = 25, n(B) = ? We know, n(A∪B) = n(A - B) + n(B - A) + n(A ∩ B) Or, 70 = 18 + 25 + n(B - A) Or, 70 = .....